-w^2+2w=40

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Solution for -w^2+2w=40 equation:


Simplifying
-1w2 + 2w = 40

Reorder the terms:
2w + -1w2 = 40

Solving
2w + -1w2 = 40

Solving for variable 'w'.

Reorder the terms:
-40 + 2w + -1w2 = 40 + -40

Combine like terms: 40 + -40 = 0
-40 + 2w + -1w2 = 0

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
40 + -2w + w2 = 0

Move the constant term to the right:

Add '-40' to each side of the equation.
40 + -2w + -40 + w2 = 0 + -40

Reorder the terms:
40 + -40 + -2w + w2 = 0 + -40

Combine like terms: 40 + -40 = 0
0 + -2w + w2 = 0 + -40
-2w + w2 = 0 + -40

Combine like terms: 0 + -40 = -40
-2w + w2 = -40

The w term is -2w.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2w + 1 + w2 = -40 + 1

Reorder the terms:
1 + -2w + w2 = -40 + 1

Combine like terms: -40 + 1 = -39
1 + -2w + w2 = -39

Factor a perfect square on the left side:
(w + -1)(w + -1) = -39

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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